Exponential Decay Calculator
Find how much remains after exponential decay.
Result
How it is calculated
The tool evaluates N = N0 × e−k×t, where N0 is the starting amount (any unit, must be above zero), k is the decay constant per unit of time and t is the elapsed time in that same unit. If k is in per-hour units, t must be in hours. It reports the remaining amount to four decimals and the percentage left, N / N0 × 100, to two decimals. If you know the half-life instead of k, use k = ln(2) / half-life, about 0.693 divided by the half-life. The tool does not reject a negative k; it then returns a value above 100%, which is exponential growth.
Worked example
Start with 200 units and a decay constant of 0.0693 per day over 10 days. Exponent: −0.0693 × 10 = −0.693. e−0.693 is about 0.50005. Remaining: 200 × 0.50005 = 100.0147. As a share of the start that is 50.01%. A constant of 0.0693 corresponds to a half-life of about 10 days, so roughly half remains.
Common mistakes
- Mixing time units: a constant per day with a time in hours or years gives an answer that is wrong by a large factor.
- Entering the half-life in the rate field. The field wants k, which is ln(2) divided by the half-life, not the half-life itself.
- Entering the decay rate as a percentage (5 for 5% per period). Use 0.05, or note that a 5% drop per period corresponds to k = −ln(0.95), about 0.0513.
- Entering a minus sign on k and expecting decay. The formula already has the minus built in, so a negative k makes the value grow.
- Reading the second result as the amount lost. It is the percentage still remaining.
About this calculator
Exponential decay describes a quantity that shrinks at a rate proportional to its current value, following N = N₀·e^(−kt), where N₀ is the initial amount, k is the decay constant, and t is elapsed time. This same equation underlies radioactive decay (where k relates to a substance's half-life via k = ln(2)/t½), drug elimination from the bloodstream in pharmacokinetics, capacitor discharge in RC circuits, and cooling of a hot object toward ambient temperature (Newton's law of cooling).
Physicists, chemists, pharmacologists, and engineers use this calculation to find how much of a radioactive isotope remains after a given time (used in carbon dating and nuclear medicine dosing), how much medication remains active in the body, or how a signal or voltage fades over time.
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Comments (1)
When you know the half-life rather than k, how many digits you keep for k matters a little. Using 0.0693 for a half-life of 10 time units leaves 50.01 percent after 10 units instead of exactly 50, while 0.693147 gives 50.00. Enter k with four or more significant digits, or the small error carries into every later period. What process are you modelling, and would a half-life input be more convenient?