Gravitational Force Calculator
Find the gravitational force between two masses.
Result
How it is calculated
The tool uses Newton's law of gravitation:
F = G × m1 × m2 / r²
G is fixed at 6.674×10-11 N·m²/kg². Masses m1 and m2 are in kilograms and the distance r is in metres, measured between the centres of the two bodies, not between their surfaces. The distance must be above zero and neither mass can be negative, or nothing is shown. The result is in newtons and printed in scientific notation with four significant digits, so 6.874 × 10² means 687.4 N. Very large numbers can be typed in e-notation too, such as 5.972e24.
Worked example
The pull of the Earth on a 70 kg person standing on the ground: m1 = 5.972e24 kg, m2 = 70 kg, r = 6.371e6 m (Earth's radius, since the centre is that far down).
- G × m1 × m2 = 6.674e-11 × 5.972e24 × 70 ≈ 2.790e16
- r² = (6.371e6)² ≈ 4.059e13
- F = 2.790e16 / 4.059e13 ≈ 6.874 × 10² N
That is about 687 N, the person's weight.
Common mistakes
- Using the distance between surfaces instead of between centres: for planets and people on them, r is the planet's radius plus any height.
- Entering masses in grams or tonnes, or distance in kilometres: the formula expects kilograms and metres, so a kilometre figure makes the force a million times too large.
- Misreading the exponent:
× 10⁻⁷is a tiny force and× 10²is hundreds of newtons, so check the sign of the exponent. - Expecting force to halve when distance doubles: it falls to one quarter, because r is squared.
About this calculator
This calculator applies Newton's law of universal gravitation, F = G(m₁m₂)/r², where G is the gravitational constant (6.674×10⁻¹¹ N·m²/kg²), to find the attractive force between two masses separated by a given distance.
Physics students use it for mechanics and astronomy homework, and it's the same formula used (in more elaborate form) to calculate orbital mechanics, satellite trajectories, and the gravitational pull between planets and stars. Because the force falls off with the square of distance, the calculator makes it easy to see why doubling the distance between two objects cuts the gravitational force to a quarter, not to a half.
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Comments (1)
The result is printed in scientific notation, and the exponent is easy to misread: × 10⁻⁵ is a hundred thousand times smaller than a result with no power of ten. Comparisons help build intuition, so try the same two masses at double the distance and the force should fall to a quarter. This is point-mass gravity, so for a large body, measure from its centre. What pair of bodies would make the most interesting example for you?