Equilibrium Constant from Gibbs Energy Calculator
Enter the Gibbs free energy change and temperature.
Result
How it is calculated
Enter ΔG in kJ/mol and the temperature in kelvin. The tool converts ΔG to joules and uses ln K = −ΔG ÷ (R × T) with R = 8.314 J/(mol·K), then K = eln K. Temperature must be above zero. K is shown to four decimals, but values below 0.0001 or at 1,000,000 and above switch to scientific notation such as 1.0188 × 10⁷. If the answer is too large for the computer to represent (an absurd ΔG such as −20000 kJ/mol), no result is shown. The spontaneity line only follows the sign of the ΔG you typed: negative is Spontaneous, positive is Non-spontaneous, exactly zero is At equilibrium. For K to be the usual equilibrium constant, ΔG should be the standard free energy change ΔG° at that temperature, and the K here is dimensionless.
Worked example
A reaction has ΔG° = −20 kJ/mol at 298.15 K. In joules that is −20,000 J/mol. R × T = 8.314 × 298.15 = 2,478.8. So ln K = 20,000 ÷ 2,478.8 = 8.0684, and K = e8.0684 = 3,191.8566. The tool shows K = 3,191.8566, ln K = 8.0684 and the label Spontaneous. K far above 1 means products are strongly favoured at equilibrium. A positive ΔG of +15 kJ/mol at the same temperature would give ln K = −6.0513 and K = 0.0024.
Common mistakes
- Entering ΔG in joules instead of kJ/mol. A value of −20000 is read as −20,000 kJ, the exponential overflows and the tool shows no result; divide joules by 1000.
- Entering the temperature in °C. Use kelvin: 25 °C is 298.15, not 25. With 25 the tool returns 6.1549 × 10⁴¹, which is nonsense but is displayed, and 0 or a negative temperature gives no result.
- Using ΔG at nonstandard conditions (with the reaction quotient Q) and expecting K. The relation K = e−ΔG°/RT needs the standard free energy change; the actual ΔG changes as the reaction proceeds.
- Confusing the sign: a negative ΔG gives K above 1, a positive ΔG gives K below 1. Reading the label Non-spontaneous as "never occurs" ignores that K = 0.0024 still means a small amount of product forms.
- Assuming ΔG is constant with temperature. The ΔG must be the value at the temperature you enter; reusing a 25 °C value at 100 °C gives the wrong K.
About this calculator
The Gibbs free energy change (ΔG) of a reaction and its equilibrium constant K are two ways of describing the same underlying thermodynamics, linked by ΔG = −RT·ln(K), where R is the gas constant and T is the absolute temperature. Rearranged to solve for K, this becomes K = exp(−ΔG / RT) — a negative ΔG (energy released) corresponds to K greater than 1, meaning products are favored at equilibrium, while a positive ΔG corresponds to K less than 1, favoring reactants.
This calculator computes K directly from a given ΔG and temperature, and reports whether the reaction is spontaneous under those conditions. It's a standard calculation in physical chemistry and biochemistry courses, and the same relationship underlies how chemists predict reaction extent, how biochemists analyze enzyme-catalyzed equilibria, and how process engineers estimate conversion yields before running a reaction.
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Comments (1)
Because K depends exponentially on the energy term, small changes in the input matter a lot. At 298.15 K, a ΔG of −10 kJ/mol gives K = 56.4965, while −11 kJ/mol gives 84.5715, about half as large again for just one extra kJ/mol. So if your ΔG comes from tabulated data with rounding, expect K to carry that uncertainty. Which reactions or textbook problems do you use this for, and at what temperatures?