HesapHanem

Hydraulic Power Calculator

Enter pressure and flow rate to calculate hydraulic power.

How it is calculated

Hydraulic power is pressure times flow. With pressure p in bar and flow Q in litres per minute, the tool converts to SI units first: P = (p × 100,000 Pa) × (Q / 60,000 m³/s) / 1000 in kW, which simplifies to p × Q / 600. Horsepower is kW × 1.34102. The kilowatts are shown with 3 decimals, the horsepower with 2, and the flow is repeated for reference. Both inputs must be above zero. The result is the power carried by the fluid at the point where you measured pressure and flow; it does not include pump efficiency or losses in hoses and valves.

Worked example

A pump delivers 40 L/min at a working pressure of 200 bar. First, 200 × 40 = 8,000, and dividing by 600 gives 13.333 kW of hydraulic power. In horsepower, 13.333 × 1.34102 = 17.88 hp. The electric motor or engine driving the pump must supply more than this, because the pump itself is not 100% efficient. The tool reports 13.333 kW and 17.88 hp.

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Common mistakes

  • Entering pressure in psi or MPa. The field is bar, so 3,000 psi is about 207 bar and 20 MPa is 200 bar.
  • Entering flow in litres per second or gallons per minute. The field is L/min.
  • Treating the result as the motor size. It is the output power of the fluid; the drive motor needs the hydraulic power divided by the pump's overall efficiency.
  • Using the relief-valve setting as the working pressure. Power depends on the pressure the system actually runs at under load, which is often lower.
  • Mixing kW with metric horsepower. The hp shown is the mechanical (imperial) horsepower, 1.34102 per kW, so it differs from the 1.36 per kW of metric horsepower.

About this calculator

Hydraulic power measures how much energy a pump or system delivers by pressurizing and moving fluid, calculated as power = pressure × flow rate. In metric units this works out to P(kW) = p(bar) × Q(L/min) ÷ 600, a shortcut hydraulic engineers use constantly when sizing components.

This figure is central to designing and troubleshooting hydraulic systems — excavators, presses, injection molding machines, and industrial pumps all depend on matching pump output power to the load they need to move. Mechanical and hydraulic engineers use it to select motors and pumps, while maintenance technicians use it to verify a system is performing to spec, converting the result to horsepower when comparing against a prime mover's rated output.

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Comments (1)

  • Editorial team

    Power that a relief valve or a restriction throttles away does not vanish; it becomes heat in the oil. If 30 L/min is dumped over a relief valve set at 200 bar, the tool's 10 kW is roughly the heat going into the tank, which is the figure to think about when sizing the reservoir or a cooler. What system are you working on, a log splitter, a press, a mobile machine? Would a pump efficiency box help you?

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